# 2017-02-24 · As the U 238 decays exponentially, the amount of Pb 206 grows correspondingly: The half - life of U 238 is about 4.5 billion years. As time passes, the ratio of Pb 206 to U 238 will increase and it is this which enables the age of the rock to be estimated.

Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))`

`t_(1//2)` of `U^(238) = 4.5 xx 10^(9)` years

A sample of rock south America contains equal number of atoms of `U^(238)` and `Pb^(206)`. The age of rock will be

Product. U-238. Pb-206. 4.5 Billion Years. U-235. Pb- 207. For example, U-238 is an ustable isotope of uranium that has 92 protons and 156 is called Pb-206 because it has 82 protons + 124 neutrons, which totals 206.

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U/Pb data aliquot #. U (ppm). Pb (ppm). 206Pb/204Pb. 207Pb/204Pb.

## isotopes used in geochronology, the constant chemical coupling of U238 and U235 with their chemically similar decay products Pb206 and. Pb207 introduces

If It Is Known That The Radioactive Material U-238 Decays To Pb-206 By Emitting Alpha And Beta Question: If It Is Known That The Radioactive Material U-238 Decays To Pb-206 By Emitting Alpha And Beta Particles A. Write Down The Core Reaction Equation? The decay of Uranium 234 to Thorium 230 is part of the much longer decay series begining in 238 U and ending in 206 Pb. For Uranium-Thorium dating, the initial ratio of 230 Th/ 234 U at the time of sample formation must be known or calculated. With time, Thorium 230 accumulates in the sample through radiometric decay.

### Question: QUESTION 1 10 Points Save Answer 1. The Decay Of U-238 To Pb-206 Can Be Used To Estimate The Age Of Inorganic Matter. The Half-life Of U-238 Is 4.5 X 109 Years. In A Particular Rock Sample, The Ratio Of The Numbers Of Pb-206 To U-238 Atoms Is 0.62.

2020-11-26 Thus, 50 gm of Pb-206 is the daughter product of radioactive decay. So, we have 50 gm radiogenic Pb-206 and 50 gm of U-238. The original amount of U-238 must have been 100 gm and we're now down to exactly half the original.

SolutionShow Solution. On emission of one alpha particle, the mass number decreases by 4. With the emission of an alpha particle, the atomic number decreases by 2 but when a β-particle is emitted, the atomic number increases by 1. \ [\ce {_92U^238-> [-α]_90X^234}\], where X represents the new nucleus. discordance = (1-(206 Pb/ 238 U age / 207 Pb/ 206 Pb age)*100 - is that right? shouldn't it be 1/(1-( 206 Pb/ 238 U age / 207 Pb/ 235 U age)*100 which in my view better describes the "distance" to
In decay from U 238 to Pb 206, each U 238 atom decays and produces 8 \(\alpha\)-particles and hence, total number of \(\alpha\)-particles emitted out = 1.204 x 10 1 8 Please log in or register to add a comment.

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In decay from U 238 to Pb 206, each U 238 atom decays and produces 8 \(\alpha\)-particles and hence, total number of \(\alpha\)-particles emitted out = 1.204 x … The sample contains 40% U-238 and 60% Pb-206. The lead content came from decay of the uranium content. Therefore we solve for the age of the sample "t" (equivalent to the decay time) using the 40% SolutionShow Solution.

Because when one mole of U-238 decays, it produces one mole of Pb-206, the amount of U-238 that has undergone radioactive decay since the rock was formed is: 2.51 × 10 −5 g Pb × ( 1 mol Pb 206 g Pb ) × ( 1 mol U 1 mol Pb ) = 1.22 × 10 −7 mol U 2.51 × 10 −5 g Pb × ( 1 mol Pb 206 g Pb ) × ( 1 mol U 1 mol Pb ) = 1.22 × 10 −7 mol U
The sample contains 40% U-238 and 60% Pb-206. The lead content came from decay of the uranium content. Therefore we solve for the age of the sample "t" (equivalent to the decay time) using the 40%
Problem : In uranium mineral, the atomic ratio $\frac{N^{U-238}}{N^{Pb-206}}$ is nearly equal to one. The age (in years) of the mineral is nearly (given that half-life of U 238 is 4.5 × 10 9 years).

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### Because when one mole of U-238 decays, it produces one mole of Pb-206, the amount of U-238 that has undergone radioactive decay since the rock was formed is: 2.51 × 10 −5 g Pb × ( 1 mol Pb 206 g Pb ) × ( 1 mol U 1 mol Pb ) = 1.22 × 10 −7 mol U 2.51 × 10 −5 g Pb × ( 1 mol Pb 206 g Pb ) × ( 1 mol U 1 mol Pb ) = 1.22 × 10 −7 mol U

because of excess radiogenic 206Pb* derived from the elevated initial 234U. The data are best interpreted using projections of a new four-dimensional concordia diagram deﬁned by 206 Pb*/ 238 U The existence of two 'parallel' uranium–lead decay routes (238 U to 206 Pb and 235 U to 207 Pb) leads to multiple dating techniques within the overall U–Pb system. The term U–Pb dating normally implies the coupled use of both decay schemes in the 'concordia diagram' (see below). However, use of a single decay scheme (usually 238 U to 206 Pb) leads to the U–Pb isochron dating method, analogous to the rubidium–strontium dating method.

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### Let N t = 1 (which is also the no of 238-U at start since 238-U decays to 206-Pb) Then N o = number of 238-U + no of of 238-U transferred to 206-Pb no of of 238-U transferred to 206-Pb = 0.603 m g / 206 g m o l ⁻¹ ∗ 238 g m o l ⁻¹ = 0.697 m g

Pb207 introduces A single detrital zircon was dated at 4.4 b.y. using the U-Pb method. 23. K-40/Ar- 40.

## 2017-02-24

Each point on the graph below represents a nuclide and each arrow represents a nuclear decay mode.

You only need how many alpha decay it undergoes . This can be determined by an equation like this #206 = 238 - (4x)# Solve for x The half-life for the decay of the Uranium (U)_238 isotope to the Lead (Pb)_206 isotope is 4.5 times 10^9 years. Mass spectrometer data for a basaltic lava sample indicates that the sample contains 40% (U)_238 and 60% (Pb)_206.